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Thermistor

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Temperature Dependent Resistor (TDR)

Negative temperature coefficient resistors (NTC Resistors)
As the temperature rises, the thermistor resistance drops.
At low temperatures, few electrons are free to move in the semiconductor material.
As the temperature rises, increased thermal vibrations cause more electrons to break free and flow.
Thermistors are used to measure temperature.
They are fairly slow to react.
Measurement circuits must be designed with care because the current flowing in the TDR must not significantly heat it up.
Note that devices like incandescent bulbs behave in the opposite way. They increase their resistance as the temperature rises. This is a positive temperature coefficient.

Thermistor Voltage Divider

Resistor NTC V Div.gif

V_out = V_s x R₂ / (R₁ + R₂)

Log Graphs

The thermistor resistance changes over such a large range that normal graphs are not useful. Log graphs solve the problem. Here is an example based on the data sheet for a thermistor with 10K at 25 C.

Thermistor Graph

At 5⁰ the resistance is 40kΩ
At 25⁰ the resistance is 200Ω
When the resistance is 3kΩ the temperature is just under 15⁰
When the resistance is 50Ω the temperature is 30⁰

Calculating a Safe Series Resistor

If possible, three design aims need to be met.

The current through the thermistor must be small so it does not heat up and alter the temperature you are trying to measure. (Alternatively, the circuit could be turned on for a short time so the thermistor does not have time to heat up.)
When the thermistor gets hot, its resistance drops close to zero. Under these conditions, the current must not exceed the maximum safe value for the thermistor.
The series resistor value should be similar to the thermistor resistance at the temperature we are trying to detect.

For example in a refrigerator, the cooling pump might come on if the temperature rises above 5 Celsius. From the graph above, the thermistor resistance is about 40kΩ. A 40kΩ series resistor could be used. In a 12 volt circuit, at 5⁰, the current flowing would be ...

I = V / R

I = 12 / 80x10³

I = 0.15 mA

This tiny current would not have much of a heating effect.

The series resistor is similar in value to the thermistor at 5⁰C.

At much higher temperatures the current would still be less that 0.3mA.

Expert Student Task

If the thermistor has a maximum heat dissipation of 0.5 Watts and the power supply voltage is 12V, at what temperature is it impossible to meet all three design requirements? You can assume that the circuit is turned for a short time so the heating effect of the current flowing can be ignored.